# Daily Quantitative Aptitude Questions 22nd June

June 22, 2017### Quantitative Aptitude Questions 22nd June:

Mathematics is one of the important sections of various Government exams, check out Daily Quant and data interpretation questions for preparation of various exams.

**Q:A>****Directions for questions 1 to 3 :** A team of 5 players Arpit, Bimal, Chatur, Dinu and Elan participated in a ‘Freaket’ tournament and played four matches (1 to 4). The following table gives partial information about their individual scores and the total runs scored by the team in each match.

Each column has two values missing. These are the runs scored by the two lowest scorers in that match.None of the two missing values is more than 10% of the total runs scored in that match.

**1) ****What is the maximum possible percentage contribution of Arpit in the total runs scored in the four matches?**

A. 19.7%

B. 19.9%

C. 20.1%

D. 20.2%

E. None of These

**2) ****If the absolute difference between the total runs scored by Arpit and Chatur in the four matches is minimum possible then what is the absolute difference between total runs scored by Bimal and Elan in the four matches?**

A. 32

B. 37

C. 27

D. Cannot be determined

E. None of These

**3) ****The players are ranked 1 to 5 on the basis of the total runs scored by them in the four matches, with the highest scorer getting Rank 1. If it is known that no two players scored the same number of total runs, how many players are there whose rank can be exactly determined?**

A. 0

B. 1

C. 3

D. 5

E. None of These

**Q:B>****Directions for questions 1 to 5 : **

**RAILWAY TIMETABLE : NEW DELHI – BHUBANESWAR RAJDHANI EXPRESS**

**1.The longest run for the train between the two successive halts is**

(a) Mughal Sarai JN – Gaya JN

(b) New Delhi – Kanpur Central

(c) Kanpur Central – Mughal Sarai JN

(d) Balasore – Balasore

(e) None Of these

**2. The average speed that the train maintained between two successive stations was the highest between**

(a) Kanpur Central – Mughal Sarai JN

(b) Mughal Sarai JN – Gaya JN

(c) New Delhi – Kanpur Central

(d) Bokaro Steel City – Tatanagar JN

(e) None Of These

**3.** **The average speed that the train maintained between New Delhi and Bhubaneswar was nearly equal to**

(a) 72 kmph

(b) 74 kmph

(c) 75 kmph

(d) 82 kmph

(e) None Of These

**4. If we consider a journey that begins in New Delhi and ends in Bhubaneswar, the train has the longest halt at**

(a) Kanpur Central

(b) Mughal Sarai JN

(c) Tatanagar JN

(d) Kharagpur JN

(e) None Of These

**5. The train begins its return journey from Bhubaneswar to New Delhi Seventeen hours after it has arrived at Bhubaneswar. If the train left New Delhi on Tuesday on what day will it have returned to New Delhi? (Assume that on the return journey that train maintains the same average speed as on the onward journey).**

(a) Thursday

(b) Friday

(c) Saturday

(d) Sunday

(e) None Of these

**Answers:**

**Q.A)**

**Option A**Explanation:Maximum possible runs scored by Arpit in Match-1 = 27Maximum possible runs scored by Arpit in Match-3 = 19Maximum possible percentage contribution:(27+100+19+53)/(270+300+240+200)x100% = 199/1010×100%

= 19.7%**Option B**Explanation:Maximum possible total runs scored by Chatur in the four matches = 27 + 30 + 110 + 20 = 187.In such a case minimum possible total runs scored by Arpit in the four matches = 23 + 100 + 13 + 53 = 189.Difference = 189 – 187 = 2 (minimum possible) Subsequently total runs scored by Bimal in the four matches = 88 + 65 + 19 + 52 = 224.Also, total runs scored by Elan in the four matches = 60 + 30 + 78 + 19 = 187Absolute difference = 224 – 187 = 37**Option C**Explanation:Individual ranges for total score:Arpit-> 189-199Bimal-> 218-224Chatur-> 182-187Dinu-> 223Elan-> 187-188

Least total will be of Chatur (Rank 5)

2nd least will be Elan (Rank 4)

Rank 3 must be of Arpit.

It is not possible to determine the exact ranks of Bimal and Dinu.

**Q.B)**

**b)-**Explanation :**With the run is of 440 km, the longest run is between New Delhi – Kanpur Central.****c)-**Explanation :**The average speed of 93.22 kmph is the highest between New Delhi – Kanpur Central.**- e)-Explanation :
**The average speed that the train maintained between New Delhi and Bhubaneswar = 1800 km/25 hrs and 25 min = 70.82 kmph.** **d)-**Explanation :**The train has the longest halt of 15 minutes at Kharagpur JN.****b)-**Explanation :**Friday**