Quantitative Aptitude Questions 21st January 2019

Quantitative Aptitude Questions 21st January 2019

January 21, 2019 0 By Anonymous

Quantitative Aptitude Questions 21st January 2019

Mathematics is one of the important sections of various Government exams, check out Daily Quant and data interpretation questions for preparation of various exams.

 


Q:A>Directions: 1-5) Study the following line graph and answer the questions based on it.

 

1)  If the % of profit on wheat is 12% what is its selling price per kg?

a) 150.08

b) 151.02

c) 162.78

d) 152.92

e) 150.62

2)  What is the difference between the cost price of butter and pulse per kg?

a) 2.5

b) 50

c) 3.34

d) 6

e) 7.54

3)  What is the selling percentage of oil? (approximation)

a) 101

b) 69

c) 65

d) 41

e) 63

4)  The average cost price of wheat, Butter and oil per kg?

a) 72

b) 61

c) 78

d) 77

e) 84

5)  If selling price of salt is Rs.57 per kg. What is total cost price of salt?

a) 400

b) 300

c) 560

d) 310

e) 350





Q:B>Study the following line graph and answer the questions based on it.

  1. If the ratio of interest rate of E to that of D is 2:3 then what is the Principal(P) of D?
    A. 15000
    B. 20000
    C. 35000
    D. 25000
    E. 30000

  2. If the interest is compounded yearly for three years then what is the amount to be earned by C?
    A. 23497.28
    B. 20497.28
    C. 22597.28
    D. 22697.28
    E. 22497.28

  3. What is the Simple Interest(SI) of B ? If the ratio of Principal of C to that of B is 4:5 and the rate of interest is 10% more than that of C.
    A. 3300
    B. 4400
    C. 2200
    D. 1100
    E. 5500

  4. If the Principal(P) of A is 20% more than that of E, then What is the amount of A?
    A. 12694.60
    B. 16584.60
    C. 12584.80
    D. 12484.80
    E. 15684.60

  5. If amount of D equals to five times that of his Principal then what is the Rate of Interest(%)?
    A. 122.22%
    B. 144.44%
    C. 133.33%
    D. 155.55%
    E. None of the Above





Answers:

Q.A)

  1. a) 150.08per kg of wheat=670/5=134100% = 134112% = xx=  (134×112)/100=150
  2. e) 7.54Butter:Selling price (Sp)=168Cost price (Cp) =(168×100)/95= 176.8Cp of butter per kg=  176.8/4= 44.21Pulse:Selling price  = 99

    Cost price =(100×99)/90  = 110

    Cp of pulse per kg=  110/3= 36.67

    Difference = 44.21-36.67= 7.54

  3. e) 63Cp = 270Sp % =  (100×170)/270=62.96
  4. d) 77Per kg of wheat =  670/5= 134Per Kg of butter =  176/4= 44Per kg of oil =  270/5 = 54Average cost =(134+44+54)/3=77
  5. b) 300Sp of salt = 56 × 6= 342Sp% => 114% = 342Cp% => 100% =   (342×100)/114=300




Q.B) DETAILED SOLUTION << CLICK HERE

  1. D
  2. E
  3. B
  4. D
  5. C