# Quantitative Aptitude Questions 21st January 2019

January 21, 2019### Quantitative Aptitude Questions 21st January 2019

Mathematics is one of the important sections of various Government exams, check out Daily Quant and data interpretation questions for preparation of various exams.

**Q:A> Directions: 1-5)**

**Study the following line graph and answer the questions based on it.**

**Q:B>Study the following line graph and answer the questions based on it.**

**If the ratio of interest rate of E to that of D is 2:3 then what is the Principal(P) of D?**

A. 15000

B. 20000

C. 35000

D. 25000

E. 30000**If the interest is compounded yearly for three years then what is the amount to be earned by C?**

A. 23497.28

B. 20497.28

C. 22597.28

D. 22697.28

E. 22497.28**What is the Simple Interest(SI) of B ? If the ratio of Principal of C to that of B is 4:5 and the rate of interest is 10% more than that of C.**

A. 3300

B. 4400

C. 2200

D. 1100

E. 5500**If the Principal(P) of A is 20% more than that of E, then What is the amount of A?**

A. 12694.60

B. 16584.60

C. 12584.80

D. 12484.80

E. 15684.60**If amount of D equals to five times that of his Principal then what is the Rate of Interest(%)?**

A. 122.22%

B. 144.44%

C. 133.33%

D. 155.55%

E. None of the Above

**Answers:**

**Q.A)**

**a) 150.08**per kg of wheat=670/5=134100% = 134112% = xx= (134×112)/100=150**e) 7.54****Butter:**Selling price (Sp)=168Cost price (Cp) =(168×100)/95= 176.8Cp of butter per kg= 176.8/4= 44.21**Pulse:**Selling price = 99Cost price =(100×99)/90 = 110

Cp of pulse per kg= 110/3= 36.67

Difference = 44.21-36.67= 7.54

**e) 63**Cp = 270Sp % = (100×170)/270=62.96**d) 77**Per kg of wheat = 670/5= 134Per Kg of butter = 176/4= 44Per kg of oil = 270/5 = 54Average cost =(134+44+54)/3=77**b) 300**Sp of salt = 56 × 6= 342Sp% => 114% = 342Cp% => 100% = (342×100)/114=300

**Q.B) DETAILED SOLUTION << CLICK HERE**

**D****E****B****D****C**